Two-Way ANOVA in R: How to Analyze and Interpret Results
Two-way ANOVA (Analysis of Variance) is a statistical method for analyzing the effect of two independent variables on a dependent (response) variable.
Two-way ANOVA is also known as two-factor ANOVA because it involves two independent variables (factor or group variables).
You can use built-in function
to perform two-way ANOVA in R.
The general syntax of
aov() function is:
# fit ANOVA model model <- aov(y ~ x1 + x2 + x1:x2, data = df) # view ANOVA summary summary(model)
||Dependent variable (should be continuous variable)|
||First independent variable (should be categorical variable)|
||Second independent variable (should be categorical variable)|
||Interaction between two independent variables|
The following comprehensive example illustrates how to use two-way ANOVA for analyzing group differences (main effects) and interaction effects. As you read this post, you will gain a deeper understanding of two-way ANOVA and its practical applications.
How to Perform Two-Way ANOVA in R
For example, a researcher wants to analyze the effect of plant genotypes and locations on the plant height. The researcher collects the data of four genotypes from three different locations and measure plant height.
The researcher wants to test the following null hypotheses:
Null Hypothesis 1: The plant height is equal among plant genotypes i.e. the mean of plant height is equal
Null Hypothesis 2: The plant height is equal at different locations i.e. the mean of plant height is equal
Null Hypothesis 3: There is no significant effect of plant genotypes and location on the height of the plants i.e. there is no significant interaction effect
Here, the alternative hypothesis is two-sided as the plant height can be lesser or greater for individual independent variables or for their interaction.
Load and view the dataset,
# load dataset df <- read.csv("https://reneshbedre.github.io/assets/posts/anova/two_way_anova.csv") # view five rows of data frame head(df) genotype location height 1 A L1 5 2 A L1 6 3 A L1 7 4 A L2 7 5 A L2 7 6 A L2 6
Check descriptive statistics (mean and variance) for each plant genotype and location,
# load package library(dplyr) # get descriptive statistics df %>% group_by(genotype, location) %>% summarise(mean = mean(height), var = var(height)) # A tibble: 9 × 4 # Groups: genotype  genotype location mean var <chr> <chr> <dbl> <dbl> 1 A L1 6 1 2 A L2 6.67 0.333 3 A L3 11 1 4 B L1 7.67 2.33 5 B L2 10 1 6 B L3 15 1 7 C L1 5.67 0.333 8 C L2 7.33 0.333 9 C L3 15.7 1.33
Visualize the box plot
# load package library("ggplot2") # create boxplot ggplot(df, aes(x = factor(genotype), y = height, fill = location)) + geom_boxplot() + geom_point(aes(fill = location), size = 4, shape = 21, position = position_jitterdodge())
From the box plot and descriptive statistics, we can see that plant height is greatly differ by genotype and location.
Now, we will perform a two-way ANOVA to check whether these differences in plant height are statistically significant and if there is a significant interaction effect between genotype and location.
Perform a two-way ANOVA and summarise the results using
# fit model model <- aov(height ~ genotype + location + genotype:location, data = df) # summary statistics summary(model) Df Sum Sq Mean Sq F value Pr(>F) genotype 2 40.67 20.33 21.11 1.90e-05 *** location 2 277.56 138.78 144.12 8.38e-12 *** genotype:location 4 23.11 5.78 6.00 0.003 ** Residuals 18 17.33 0.96 --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Note: This ANOVA is performed for a balanced design i.e. equal sample size for each group. If you have an unbalanced design, you should perform an ANOVA with type III sums of squares.
The two-way ANOVA analysis reports the following important statistics for main effects and interaction effects,
|genotype (main effect)||21.11||1.90e-05|
|location (main effect)||144.12||8.38e-12|
|genotype:location (interaction effect)||6.00||0.003|
According to the two-way ANOVA results, the p value is significant [F(2, 18) = 21.11, p < 0.05] for genotype. Hence, we reject the null hypothesis and conclude that plant height among genotypes is significantly different.
Similarly, the p value is significant [F(2, 18) = 144.12, p < 0.05] for location. Hence, we reject the null hypothesis and conclude that location has a significant effect on plant height.
The interaction between plant genotypes and location is also significant [F(4, 18) = 6, p < 0.05]. Hence, we reject the null hypothesis, and conclude that both plant genotypes and location significantly influence plant height.
Enhance your skills with courses on Statistics and R
- Introduction to Statistics
- R Programming
- Data Science: Foundations using R Specialization
- Data Analysis with R Specialization
- Getting Started with Rstudio
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